Question

What is the general form of the equation of the given circle with center A?

Answer 1

I think it's 2r=(-3,12)

Answer 2

Answer-

General form of the given circle is,

$(x+3)^2+(y-12)^2=5^2$

Solution-

The general form of the circle is,

$(x-h)^2+(y-k)^2=r^2$

Where,

(h, k) is the co-ordinate of the center and r is the radius of the circle

Here,

h = -3, k = 12, r = 5

So putting the values,

$\Rightarrow (x-(-3))^2+(y-12)^2=5^2$

$\Rightarrow (x+3)^2+(y-12)^2=5^2$

$\Rightarrow (x^2+9+6x)+(y^2+144-24y)=25$

$\Rightarrow x^2+y^2+6x-24y+128=0$