What is the general form of the quadratic function given the vertex (4, -1) and the values of a equals 1?
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4 is the general form of the quardratic function
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HI GUYS,
YOUR ANSWER IS HERE
PROOF:-
VERTEX(4,-1) GIVEN
AND EQUALS TO 1
If an equation representing a parabola is in vertex form such as:-
y=a(x-k)^2+h
then its vertex will be at (k ,h). Therefore the equation for a parabola with a vertex at (4,-1), will have the general form,
y=a(x-4)^2+(-1)
y= -1 GIVEN
-1 = a(x^2 + 16 - 8x) - 1
0 = a (x^2 + 16 - 8x)
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