Math, asked by lvramity, 7 hours ago

What is the general form of the quadratic function given the vertex (4, -1) and the values of a equals 1?

Answers

Answered by swathis1604
0

Answer:

4 is the general form of the quardratic function

Answered by SONAXRAMPY
2

Answer:

HI GUYS,

YOUR ANSWER IS HERE

PROOF:-

VERTEX(4,-1) GIVEN

AND EQUALS TO 1

If an equation representing a parabola is in vertex form such as:-

y=a(x-k)^2+h

then its vertex will be at  (k ,h). Therefore the equation for a parabola with a vertex at (4,-1), will have the general form,

y=a(x-4)^2+(-1)

y= -1 GIVEN

-1 = a(x^2 + 16 - 8x) - 1

0 = a (x^2 + 16 - 8x)

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