Physics, asked by vaidiksharma9, 1 year ago

what is the genetical radiation retaliation of gamma radiation

Answers

Answered by aqdaskhan11
1
alpha beta and gama hope it is correct...
Answered by radhika68825
1
The DNA of a gene 2 mutant (T4 2-) of phage T4 is degraded by RecBCD enzyme in the bacterial cytoplasm. Under normal conditions, recBCD+ cells are therefore incapable of supporting the growth of phage T4 2-. Only if the nucleolytic activity of RecBCD enzyme is absent from the cytoplasm are T4 2(-)-infected bacteria able to form plaques. We found that recBCD+ cells can form plaques if, before infection with T4 2-, they have been exposed to gamma radiation. It is suggested that gamma ray-induced lesions of the bacterial DNA (e.g., double-strand breaks) bind RecBCD enzyme. This binding enables the enzyme to begin to degrade the bacterial chromosome, but simultaneously prevents its degradative action on the ends of minor DNA species, such as unprotected infecting phage chromosomes. Degradation of the chromosomal DNA, which occurs during the early postirradiation period, ceases about 60 min after gamma ray exposure. The reappearance of the nucleolytic action of RecBCD enzyme on T4 2- DNA accompanies the cessation of degradation of bacterial DNA. Both, this cessation and the reappearance of the nucleolytic action of ReCBCD enzyme on T4 2- DNA depend on a functional recA gene product. These results suggest that postirradiation DNA degradation is controlled by the recA-dependent removal of RecBCD enzyme from the damaged chromosome. By making use of the temperature-sensitive mutant recB270, we showed that RecBCD-mediated repair of gamma ray-induced lesions occurs during the early postirradiation period, i.e. during postirradiation DNA degradation. It is shown that the RecD subunit of RecBCD enzyme also participates in this repair.
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