Question

What is the geometry of [Fe(CN)6]^3- according to VBT?​

Answer 1

Answer:

The central metal has an oxidation number +3 calculated as:

x + 6 × (−1) = −3

(1) Hybridization – d2sp3

(2) Magnetic behaviour – Paramagnetic in nature

(3) The oxidation state of Fe = -3

Answer 2

Explanation:

$\mathsf{[Fe(CN)_{6}] {}^{3 - } }$

Calculation of O.N. -

→ x - 1×6 = -3

→ x = 3

Electronic configuration of Fe

• $\mathsf{[Ar] 4s {}^{2} 3d {}^{6} }$

Then,

Electronic configuration of Fe³+

• [Ar] 3d⁵

Orbital diagram -

( Refer to the attachment. )

Calculation of C.N. -

→ 1 × 6

→ 6

CN- is a strong field ligan. So, electrons pairs up.

Hence,

Hybridisation = d²sp³

Number of unpaired electron = 1

Magnetic Behaviour = paramagnetic

magnetic moment (μ) = √n(n+2) B.M.

→ √1(1+2)

→ √3 B.M.