What is the gravitational field intensity on the surface of a planet if it's mass is doubled and radius is four times that of the earth?
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Answered by
3
7
acceleration due to gravity becomes twice of original.
formula for acceleration due to gravity is
g=g
_
m
G is a constant equal to 6.67 × 10-11 N-m2/kg2,
M is mass of planet which is also a constant
r is radius of planet which is also a constant
if mass and radius are half of original i.e M/2 and r/2
g'=G(M/2)/(r/2)^2
which gives g' = 2GM/r^2
g'=2g
acceleration due to gravity got twice of original
acceleration due to gravity becomes twice of original.
formula for acceleration due to gravity is
g=g
_
m
G is a constant equal to 6.67 × 10-11 N-m2/kg2,
M is mass of planet which is also a constant
r is radius of planet which is also a constant
if mass and radius are half of original i.e M/2 and r/2
g'=G(M/2)/(r/2)^2
which gives g' = 2GM/r^2
g'=2g
acceleration due to gravity got twice of original
anuchopra:
Hi
But the options are
a.2/4 times of earth
b.8 times of the earth c.1/8 times of the earth d.1/16times of the earth
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Brainly.in
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What is the gravitational field intensity on the surface of a planet if it's mass is doubled and radius is four times that of the earth?
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Anuchopra ·
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dghyfunkjfx
Dghyfunkjfx Virtuoso
7
acceleration due to gravity becomes twice of original.
formula for acceleration due to gravity is
g=g
_
m
G is a constant equal to 6.67 × 10-11 N-m2/kg2,
M is mass of planet which is also a constant
r is radius of planet which is also a constant
if mass and radius are half of original i.e M/2 and r/2
g'=G(M/2)/(r/2)^2
which gives g' = 2GM/r^2
g'=2g
Brainly.in
What is your question?
Secondary SchoolPhysics 5+3 pts
What is the gravitational field intensity on the surface of a planet if it's mass is doubled and radius is four times that of the earth?
Ask for details FollowReport by Wwwsamragyeesw 4 minutes ago
Answers
Anuchopra ·
Know the answer? Add it here!
dghyfunkjfx
Dghyfunkjfx Virtuoso
7
acceleration due to gravity becomes twice of original.
formula for acceleration due to gravity is
g=g
_
m
G is a constant equal to 6.67 × 10-11 N-m2/kg2,
M is mass of planet which is also a constant
r is radius of planet which is also a constant
if mass and radius are half of original i.e M/2 and r/2
g'=G(M/2)/(r/2)^2
which gives g' = 2GM/r^2
g'=2g
Hi
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