Physics, asked by wwwsamragyeesw, 1 year ago

What is the gravitational field intensity on the surface of a planet if it's mass is doubled and radius is four times that of the earth?

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Answered by dghyfunkjfx
3
7

acceleration due to gravity becomes twice of original.

formula for acceleration due to gravity is 

g=g
_
m

G is a constant equal to 6.67 × 10-11 N-m2/kg2,
M is mass of planet which is also a constant
r is radius of planet which is also a constant

if mass and radius are half of original i.e M/2 and r/2

g'=G(M/2)/(r/2)^2
which gives g' = 2GM/r^2
g'=2g
acceleration due to gravity got twice of original




anuchopra: Hi
wwwsamragyeesw: But the options are
wwwsamragyeesw: a.2/4 times of earth
wwwsamragyeesw: b.8 times of the earth c.1/8 times of the earth d.1/16times of the earth
Answered by anuchopra
0
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What is the gravitational field intensity on the surface of a planet if it's mass is doubled and radius is four times that of the earth?
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dghyfunkjfx
Dghyfunkjfx Virtuoso
7

acceleration due to gravity becomes twice of original.

formula for acceleration due to gravity is

g=g
_
m

G is a constant equal to 6.67 × 10-11 N-m2/kg2,
M is mass of planet which is also a constant
r is radius of planet which is also a constant

if mass and radius are half of original i.e M/2 and r/2

g'=G(M/2)/(r/2)^2
which gives g' = 2GM/r^2
g'=2g

anuchopra: Hi
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