Question

what is the gravitational force between the earth (M = 6x10²⁴ kg) and 1 kg object (m=1kg) on surface of The earth radius (r) of earth is 6.4 x 10⁶ m d = 6.4x10⁶m​

Answer 1

Answer:-

9.77N

Given :-

• Mass of the earth is (M) = 6 ×10²⁴ kg
• mass of the object (m) = 1kg
• Radius of the earth (r) = 6.4 × 10⁶

To find :-

• Gravitational force of the body

SOLUTION :-

For finding the Gravitational force of the body we have formula that is

F = GMm/r²  

where ,

• G is the Gravitational constant [6.67×10^-11]
• M is the mass of earth
• m is the mass of object
• r is the radius  

Substituting the values ,

Have a look on calculation !

F = 6.67×10⁻¹¹ × 6 × 10²⁴×1/ (6.4×10⁶)²

F = 6.67×6×10¹³ / 6.4× 6.4 10¹²

F = 6.67×6 ×10¹³×10⁻¹²/6.4×6.4

F = 6.67×6×10/6.4×6.4

F = 6.67×60/6.4×6.4

F = 667×60/64×64

F = 40,020/4096

F = 9.77 N

So, the Gravitational force acting on the body is 9.77N