Physics, asked by chems, 1 year ago

what is the gravitational forces of attraction due to a hollow spherical she'll of uniform density of a point mass situated inside it? for 1 mark answer

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Answered by Anonymous
2

Gravity does cancel out for all points inside a hollow spherical shell.  That is, assume there is no air inside a soccer ball, the gravity from  the soccer ball on an ant floating anywhere inside the ball will sum to zero. This can be shown by adapting the integral form of Gauss's Law  replacing the magnetic field with the gravitational field.


If you are  not yet familiar with vector calculus in order to use Gauss's Law  directly, then you can simply think about it this way. In the exact  middle of the hollow shell, there will be a gravitational pull from  every point on the shell, but each point will have a different  direction. In fact, for every point with a gravitational pull in one  direction, there is a point on the exact opposite side of the ball with  the same amount of pull but in the opposite direction.


As you move from the middle to some other point inside the ball, you  move closer to one edge of the ball than the other, and thus the forces  from one side become stronger than the other. However, there is a  competing change, as you move towards one side of the ball the amount of  material behind you gets large, as you get closer to the material in  front of you, these two competing changes will tend to cancel each  other. What Gauss's Law beautifully proves, and what you may not guess  intuitively, is that these two competing changes actually cancel each  other exactly. Thus there is no net gravitational force anywhere inside the hollow spherical shell

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