Question

what is the greast number which when divides 3026 and 5053 leaves remainders 11 and 13 respectively?

Answer 1

Answer:

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Answer 2

To find required number we have to find HCF of (3026−11) and (5053−13)

Now, HCF of 3015 and 5040

To find HCF, we break the given numbers in their prime Factors.

3015=3×3×5×67

5040=2×2×2×2×3×3×5×7

We take common multiples in these two given numbers to get required HCF.

And Common multiples are: 3×3×5

So, Required HCF = 45.

∴ The required number is 45.