What is the greater of the two numbers whose product is 640, if the sum of the two numbers exceeds their difference by 32?
Answers
Answered by
3
Let the first no. be=x
Let the second no. be=y
XY=640
X+Y=(X-Y)+32
X-X+Y+Y=+32
2Y=+32
Y=32/2
Y=16 ANS.
Answered by
1
Answer:
The two numbers are 40 and 16
Explanation:
Let the number be x and y
Here x > y
According to the question,
=> (x + y) - (x - y) = 32
=> x + y - x + y = 32
=> 2y = 32
=> y = 16 ans.
Now,
Their product is 640
So,
=> xy = 640
=> 16x = 640
=> x = 640/16
=> x = 40 ans.
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