Math, asked by paavnipuri31, 10 months ago

What is the greatest 5-digit no. Which when divided by 8,14,18,24 and 48 leaves a remainder of 6 in each case ?

Answers

Answered by Dharshini1359

Answer:

I think it 65789

Step-by-step explanation:

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Answered by saikumar17121

Answer:

Multiply 99 by 1008 and add 7 to get 99792+7 = 99799 as the largest 5-digit number divisible by 8, 14, 18, 24 and 48 leaving a remainder of 7 in each case.

I hope U will understand

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