Question

What is the greatest 5-digit number which when divided by 2, 3, 4, and 5 leaves a remainder of 1 in each case?

Answer 1

Answer:

1)Take LCM of 2,3,4,5 and Lcm=120

2)Greatest 5 digits number=99999

3)Divide 99999 from 120

4) you get 833.32

5)Subtract 833.32 from 99999 you get 99165.68

6) Add 1 in 99165.68,you get 99166.68

7)99166.68 is your answer