Math, asked by shajisaifina7310, 1 year ago

what is the greatest integer k for which 32.45*10^k is less than 1

Answers

Answered by zoya70
1
I think it will be yes.
Answered by athleticregina
1

Answer:

k = 2

0.3245\times 10^{2}<1

Step-by-step explanation:

 Given : expression 32.45\cdot 10^{k}

We have to find the greatest integer k for which 32.45\cdot 10^{k} is less than 1

Since, we have write   32.45\cdot 10^{k}  less than 1

we can write  32.45\cdot 10^{k} in scientific notation

Scientific notation is a way of writing large numbers less than 1 using notation by dividing by power of 10 to shift the decimals toward left.

a\cdot 10^{n} , where 0< a < 10 and n is integer.

Thus, to make 32.45\cdot 10^{k}  less than 1

Divide and multiply 32.45 by 100 , we get

\frac{32.45\times 100}{100}=0.3245\times 10^{2}

Thus, on comparing k = 2

0.3245\times 10^{2}&lt;1

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