What is the greatest integer not exceeding the sum sigma (n=1 till 1599 )1/sqrt(n)
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Answer:
the greatest integer not exceeding the sum = 78
Step-by-step explanation:
What is the greatest integer not exceeding the sum sigma (n=1 till 1599 )1/sqrt(n)
1/√n = 2/2√n
= 2/(√n + √n)
2/(√n + √n) > 2/(√n + √n+1)
by rationalizing
2/(√n + √n+1) = 2(√n+1 - √n)
=> 1/√n > 2(√n+1 - √n)
By Adding all terms from 1 to 1599 we will get
2(√1600 - 1) (as all other terms will get cancelled)
= 2(40 - 1)
= 78
=> sum > 78
2/(√n + √n) < 2/(√n + √n-1)
by rationalizing
2/(√n + √n-1) = 2(√n - √n-1)
By Adding all terms from 2 to 1599 we will get
2(√1599 - 1) (as all other terms will get cancelled)
= 77.98
1/√1 + 77.98 = 78.98
=> sum < 78.98
=> 78 < Sum < 78.98
the greatest integer not exceeding the sum = 78
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