Math, asked by ananyaborah1, 3 months ago

what is the greatest no of three digits which when divided by 12,15,24 and 40 leaves 9,12,21 and 27 respectively as remainder

Answers

Answered by gadityamanikumar567

Step-by-step explanation:

How do I find the largest five-digit number which, when divided by 9, 12, 24 and 45, leaves remainders of 3, 6, 18, and 39, respectivly?

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Mohan Kerish

Answered September 24, 2017

From the info provided in the qstion we can identify that ..

The difference between the divisor and the remainder is same in all the cases which is 6

STEP 1:

LCM OF DIVISORS

LCM OF( 9,12,24,45) IS 360

STEP 2:

We know the largest five digit number is 99999

Now to find the largest five digit number which satisfy the given conditons then do the following

A) 360*N-6

N, is the quotient of 99999/360

U will get the answer as 360*277–6= 97214

B) Divide 99999/360

U will get remainder as 279

SUBTRACT 279 FROM 99999 WHICH IS 99720

Now 99720–6= 97214 which will be ur answer

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