Question

what is the greatest no that can divide 664 and 170 with remainders 1and 2 respectively​

Answer 1

Solution :-

We need to find the greatest number that can divide 664 leaving remainder 1 and divide 170 leaving remainder 2 .

So,

→ The required number = HCF of (664 - 1) and (170 - 2) = HCF(663 , 168)

checking prime factors of 663 and 168 we get,

→ 663 = 3 * 13 * 17

→ 168 = 2 * 2 * 2 * 3 * 7

then,

→ HCF = 3

Hence, the required greatest number is equal to 3 .

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