What is the greatest number by which if 1023 and 750 be divided 3 and 2 are left as remainders ?
Answers
Answered by
28
The greatest number by which if 1023 and 750 be divided 3 and 2 are left as remainders is 68.
Solution:-
1st number = 1023
Remainder = 3
= 1023 - 3
= 1020
2nd number = 750
Remainder = 2
= 750 - 2
= 748
H.C.F of 1020 & 748 = 68
Hence, the required number is 68.
Solution:-
1st number = 1023
Remainder = 3
= 1023 - 3
= 1020
2nd number = 750
Remainder = 2
= 750 - 2
= 748
H.C.F of 1020 & 748 = 68
Hence, the required number is 68.
rahamatkhan96:
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Answered by
11
Solution:-
1023 - 3 = 1020
750 - 2 = 748
1020 = 2*2*3*5*17
748 = 2*2*11*17
H.C.F. of 1020 and 748
= 2*2*17 = 68
So 68 is the greatest number by which if 1023 and 750 are divided we will get 3 and 2 as remainders respectively.
Answer.
1023 - 3 = 1020
750 - 2 = 748
1020 = 2*2*3*5*17
748 = 2*2*11*17
H.C.F. of 1020 and 748
= 2*2*17 = 68
So 68 is the greatest number by which if 1023 and 750 are divided we will get 3 and 2 as remainders respectively.
Answer.
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