What is the greatest number by which if 1023 and 750 be divided 3 and 2 are left as remainders
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The greatest number by which if 1023 and 750 be divided 3 and 2 are left as remainders is 68.
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Solution:-
1023 - 3 = 1020
750 - 2 = 748
1020 = 2*2*3*5*17
748= 2*2*11*17
H.C.F. of 1020 and 748
= 2*2*17
= 68
So, 68 is the greatest number by which if 1023 and 750 are both divided then we will get 3 and 2 as remainders respectively.
1023 - 3 = 1020
750 - 2 = 748
1020 = 2*2*3*5*17
748= 2*2*11*17
H.C.F. of 1020 and 748
= 2*2*17
= 68
So, 68 is the greatest number by which if 1023 and 750 are both divided then we will get 3 and 2 as remainders respectively.
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