Math, asked by sadman12, 7 months ago

What is the greatest number of 4 digits which is divided by 12 15,20,35 with 10 as remainder in every case​

Answers

Answered by mathdude500
10

Prime factor of 12 = 2×2×3

Prime factor of 15 = 3×5

Prime factor of 20 = 2×2×5

Prime factor of 35 = 5×7

LCM of 12, 15, 20, 35 = 420

Largest 4 digit number = 9999

Divide 9999 by 420, we get quotient as 23.

So it means largest 4 digit number is 9660 which is divisible by 12, 15, 20, 35.

So largest 4 digit number which leaves remainder 10 when divided by 12, 15, 20, 35 = 9670.

Answered by suman8615
0

Answer:

this is correct........................................

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