Question

What is the greatest number that divides 30, 53, 99 to leave the same remainder

Answer 1

Answer:

53 is the answer.........

Answer 2

$Find \:out \:the \:HCF \: of \: the \: given \\three \: numbers \: obtained \:from \:the \\mutual \:subtraction .$

$On \:mutual \:subtraction ,\:we \:get$

(53 - 30 ) = 23

( 99 - 53 ) = 46

( 99 - 30 ) = 69

$HCF \: of \: 23 , 46 \:and \: 69 = 23$

Therefore.,

$\red { Required \: number } \green {= 23 }$

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