What is the greatest number that divides 770 and 326 leaving any remainder
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Answered by
4
Answer:
Since we require 2 as the remainder we will subtract 2 from each of the numbers
167−2=165
134−2=132
Now any of the common factors of 165 and 132 will be the required divisor
On factorization
165=3×5×11
132=2×2×3×11
Their common factors are 11 and 3=11×3=33
Hence 33 is the required divisor
Step-by-step explanation:
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Answered by
0
Answer:
Answer is 33
Step-by-step explanation:
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