What is the greatest number that will divide 2400 and 1810 and leave remainders 6 and 4 respectively
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The required number is 42.
Step-by-step explanation:
We have to find the greatest number that will divide 2400 and 1810 and leave remainders 6 and 4 respectively.
So, the required number will divide (2400 - 6) = 2394 and (1810 - 4) = 1806 completely with zero remainder.
Therefore, the required number is the greatest common factor of 2394 and 1806.
Now, we can write 2394 = 2 × 3 × 3 × 7 × 19 and we can write 1806 = 2 × 3 × 7 × 43
Therefore, the greatest common factor is 2 × 3 × 7 = 42.
So, the required number is 42. (Answer)
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