Question

what is the greatest number that will divide 307 and 330 having remainder 3 and 7 respectively​

Answer 1

Answer:

The number will be HCF of 307 – 3 = 304 and 330 – 7 = 323.

Step-by-step explanation:

As we know that the largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r).

The number will be HCF of 307 – 3 = 304 and 330 – 7 = 323.

∴ Required number = 19

Answer 2

$answer$

Hye

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aim : to find What is the greatest number that will divide 307 and 330 leaving remainders 3 and 7 respectively

=> forst let us detect 307 and 330

=>307 -3= 304

=> 330 - 7 =323

now let us find the hcf of 304 and 323

=> 323=1,17,19,323,

=>304 = : 1,2,4,8,16,19,38,76,152,304

hcf is 19

so 19 largest positive integer that will divide divide 307 and 330 leaving remainders 3 and 7 respectively

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hope it helsp u..............