Question

what is the greatest number which divides 615 and 963 leaving remainder 6 in each case.

Answer 1

Here is your answer dear :-)

To find the greatest number which divides 615 and 963 leaving remainder 6 in each case, we have to take HCF.

Let the HCF be x

In order to make the HCF divisible by 615 and 963 we must deduct 6 from both the numbers.

Therefore, 615 - 6 = 609, 963 - 957

609 = 3 x 3 x 29

957= 3 x 11 x 29

⇒ x = 3 x 29 = 87

∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87

Answer 2

Answer:

Hope its helpful for you.....