What is the greatest number which divides 967 and 1463 to give remainder 7 in each case? in class 5
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Answered by
5
Answer:
Step-by-step explanation:
2053 - 5 = 2048 and 967 - 7 = 960
Prime factorisation of 2048 and 960 are as follows,
2048 = 211 and 960 = 26 × 3 × 5
HCF(2048, 960) = 26 =64
Therefore, the largest number which divides 2053 and 967 and leaves remainder 5 and 7 respectively is 64.
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Answered by
4
Answer:
sorry
Step-by-step explanation:
cant solve
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