what is the greatest number which when divides 3026 and 5053 leaves remainder 11 and 13 respectively?
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Answer:
45
Step-by-step explanation:
subtract 11 from 3026 and 13 from 5053
3026 - 11 = 3015
5053 - 13 = 5040
HCF of 3015 and 5040
3,015 = 3 × 3 × 5 × 67
5,040 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 7
HCF of 3015 and 5040 = 3 × 3 × 5 = 45
45 divides 3026 and 5053 leaving remainder 11 and 13 respectively.
3026 = (45 × 67) + 11
5053 = (45 × 112) + 13
hope you get your answer
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