Question

What is the greatest number which will divide 110 and 128 leaving a remainder 2 in each case?

Answer 1

Subtract remainder 2 from given numbers then find hcf
After subtracting 2 we get
108 and 126
126=2×3×3×7
108=2×2×3×3×3
Hcf =2×3*3=18
18 is the largest number which divides 110 and 128 leaving a remainder 2 in each case

Answer 2

18

Answers

110-2=108

128-2=126

step-by-step explanation

HCF of 108and 126=18

108= 2×2×3×3×3

126=2×7×3×3

2×3×3=18