What is the greatest of 3 consecutive integers whose sum is 24 ?
A) 6
B) 7
C) 8
D) 9
Answers
x+x+1+x+2=24
3x+3=24
x+1=8
x=7
greatest of the three no.s is x+2=7+2=9
answer=D)9
Concept:
The numbers that come after one another are known as consecutive integers. They proceed sequentially or alphabetically. For instance, a group of natural numbers is a sequence of integers. In mathematics, the term "consecutive" refers to an uninterrupted succession or a continuous flow of numbers, so that successive integers follow a sequence in which each succeeding number is one more than the one before it. The mean and median in an array of successive integers (or in numbers) are both identical. In the event that x is an integer, then x + 1 and x + 2 are also integers.
Given:
The number is 24.
Find:
We have to find the greatest of 3 consecutive integers whose sum is 24.
Solution:
Let's take the consecutive integer as x, (x + 1) and (x + 2).
Now, we have to use this integers as a sum of 24.
x + (x + 1) + (x + 2) = 24
3x + 3 = 24
3x = 21
x = 7
So, first integer x = 7
Second integer = x + 1 = 8
Third integer = x + 2 = 9
From 7, 8 and 9 the greatest of 3 consecutive integers whose sum is 24 is 9.
Hence, option (D) 9 is correct.
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