Question

what is the greatest possible area pf a right angled traingle whose hypotenuse is 4 cm​

Answer 1

we know that about right angled triangle,

let Hypotenuse is h , length is l and Breadth is b,

(Hypotenuse)^2 = (Length)^2+(Breadth)^2

h^2 = l^2+b^2

so that

4^2 = l^2+b^2

16 = l^2+b^2

16 = 3^2+2^2

16 = 9 + 4

16 is not equals to 13 because we can't take value great than hypotenuse

so I think greatest possible area is,

1/2×3×2=3cm^2