Math, asked by pinkikumaripinkikuma, 7 months ago

what is the H. C. f of 267;445;712​

Answers

Answered by dharmisthavaland25
0
3/267 (1)
89/89
/1


(2) 5/445
89/89
/1


(3) 2/712
2/356
2/178
89/89
/1


Hope it will help you









Answered by akash072005
0

Step-by-step explanation:

267 = 3× 89

445 = 5×89

712 = 2×2×2×89

as because here in the prime factorisation of all the three no. we get to find that 89 is common ,so that's why we will do 89×89×89 =89^3. that is equal to 704969.

so. the HCF og 267,445,712 is 704969

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