What is the half of the area of the triangle whose vertices are (1,1),(3, 1), (1, 3)
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Answer:
Given:
A(1,1) B(3,1) c (1,3)
To Find:
half of area of triangle
Proof:
area of triangle = 1/2 | x1(y2 - y3) + x2 ( y3-y1) + x3 ( y2-y1)^2
area = 1/2 | 1(1-3) + 3(3-1) + 1(1-1)|
= 1/2 | -2+6|
= 2 square units
half of area of rectangle = 1/2 [2] = 1 sq units
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