What is the hcf of 512,408,748
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We have to find the HCF of 748, 408 and 512.
We will find the HCF of given numbers using prime factorisation method.
The prime factorisation of 748, 408 and 512
are :
748 = 2 × 2 × 11 × 17
408 = 2 × 2 × 2 × 3 × 17
512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2
HCF (748, 408, 512) = 2 × 2 = 4
We will find the HCF of given numbers using prime factorisation method.
The prime factorisation of 748, 408 and 512
are :
748 = 2 × 2 × 11 × 17
408 = 2 × 2 × 2 × 3 × 17
512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2
HCF (748, 408, 512) = 2 × 2 = 4
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Answer: HCF of 748,408and 512 by short division method
Step-by-step explanation:
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