What is the HCF of 63,45 and 20
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HCF of 63, 45, 20, is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 63, 45, 20 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 63, 45, 20 is 1.
HCF(63, 45, 20, 274) = 1
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Answer:
The factors of 45 and 63 are 1, 3, 5, 9, 15, 45 and 1, 3, 7, 9, 21, 63 respectively.
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