what is the hcf of 960and 1575 sing euclid division algorithm
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Step 1:-
1575 = 960 × 1 + 615
Step 2 :-
960 = 615 × 1 + 345
Step 3 :-
615 = 345 × 1 + 270
Step 4 :-
345 = 270 × 1 + 75
Step 5 :-
270 = 75 × 3 + 45
Step 6 :-
75 = 45 × 1 + 30
Step 7 :-
45 = 30 × 1 + 15
Step 8 :-
30 = 15 × 2 + 0
Remainder = 0
So,
HCF ( 960, 1575) = 15
1575 = 960 × 1 + 615
Step 2 :-
960 = 615 × 1 + 345
Step 3 :-
615 = 345 × 1 + 270
Step 4 :-
345 = 270 × 1 + 75
Step 5 :-
270 = 75 × 3 + 45
Step 6 :-
75 = 45 × 1 + 30
Step 7 :-
45 = 30 × 1 + 15
Step 8 :-
30 = 15 × 2 + 0
Remainder = 0
So,
HCF ( 960, 1575) = 15
Anonymous:
Nice solution bro.
Answered by
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Hello , dear ...★
here , is Ur answer .
HOPE it's helps u☺☺☺
___ Euclid's division Algorithm ____
Apply Euclid's division lemma
a = b × q + r
Dividend = Divisor × Quotient + Remainder
Here, Q . is given Find the H.C.F of 960 and 1575 .
Sol. ...
-step :1. since 1575 > 960 .
we apply the division lemma to 1575 and 960 to get,
=> 1576 = 960 × 1 + 615
=> 960 = 615 × 1 + 345
=> 615 = 345 × 1 + 270
=> 345 = 270 × 1 + 75
=> 270 = 75 × 3 + 45
=> 75 = 45 × 1 + 30
=> 45 = 30 × 1 + 15
=> 30 = 15 × 2 + 0
The remainder has now become zero, so our procedure stops.
since, the Divisor at this step is 15 .
The H.C.F of 960 and 1575 is 15
ANS- 15
here , is Ur answer .
HOPE it's helps u☺☺☺
___ Euclid's division Algorithm ____
Apply Euclid's division lemma
a = b × q + r
Dividend = Divisor × Quotient + Remainder
Here, Q . is given Find the H.C.F of 960 and 1575 .
Sol. ...
-step :1. since 1575 > 960 .
we apply the division lemma to 1575 and 960 to get,
=> 1576 = 960 × 1 + 615
=> 960 = 615 × 1 + 345
=> 615 = 345 × 1 + 270
=> 345 = 270 × 1 + 75
=> 270 = 75 × 3 + 45
=> 75 = 45 × 1 + 30
=> 45 = 30 × 1 + 15
=> 30 = 15 × 2 + 0
The remainder has now become zero, so our procedure stops.
since, the Divisor at this step is 15 .
The H.C.F of 960 and 1575 is 15
ANS- 15
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