what is the hcf of 96and404
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1
96= 2×2×2×2×2×3
= 2power 5× 3 power 1
404 = 2×2×101
= 2power 2× 101 power 1
= 2power 5× 3 power 1
404 = 2×2×101
= 2power 2× 101 power 1
Answered by
1
4
404=96 x 4 + 20
96= 20 x 4 + 16
20= 16 x 1 + 4
16= 4 x 4 + 0
hence, hcf of 96&404 is 4
404=96 x 4 + 20
96= 20 x 4 + 16
20= 16 x 1 + 4
16= 4 x 4 + 0
hence, hcf of 96&404 is 4
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