what is the HCF of k, 2k,3k,4k,5k
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the answer will be 'k'
Answered by
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^_^
To find out :-
HCF ( k , 2k , 3k , 4 k , 5 k )
Solution :-
First of all , we will do prime factorisation of all the numbers .
k = k
2k = k * 2
3k = k * 3
4k = k * 4
5k = k * 5
Now , we see that k is common in every number .
So ,
HCF ( k , 2k , 3k , 4k , 5k ) = k
^_^
To find out :-
HCF ( k , 2k , 3k , 4 k , 5 k )
Solution :-
First of all , we will do prime factorisation of all the numbers .
k = k
2k = k * 2
3k = k * 3
4k = k * 4
5k = k * 5
Now , we see that k is common in every number .
So ,
HCF ( k , 2k , 3k , 4k , 5k ) = k
^_^
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