Question

what is the HCF of this 1st expression. xy2-y2​

Answer 1

Step-by-step explanation:

1st expression=x^2-xy-2y^2

=x^2-(2-1)xy-2y^2

=x^2-2xy+xy-2y^2

=x(x-2y)+y(x-2y)

=(x+y)(x-2y)

2nd expression=2x^2-xy-y^2

=2x^2-(2-1)xy-y^2

=2x^2-2xy+xy-y^2

=2x(x-y)+y(x-y)

=2x+y(x-y)

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Answer 2

Answer:

Correct option is

A

1

Factorizing

x

2

y and xy

2

,

x

2

y=x∗x∗y

xy

2

=x∗y∗y

H.C.F. =x∗y L.C.M.=x∗x∗y∗y=x

2

y

2

Step-by-step explanation:

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