What is the heat energy required to melt an ice slab of mass 3 Kg? The specific heat of water is 4180 J / Kg / K.
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The heat required to bring ice to 0°C i.e 273 K.
Q=mct
Q=3×4180×273
Q=34,23,420 J
If you want to solve it further.
The heat required to change the phase of a substance is given by the equation:
Q= mL (Q= Heat required, m= mass, L= Latent Heat of Fusion/Evaporation/Anything else).
So, to convert ice at 0°C to water at 0°C
Q= 3.0 kg x 333 kJ/Kg
So, Q= 999 kJ
Total energy=(3423420+999)J
Q=mct
Q=3×4180×273
Q=34,23,420 J
If you want to solve it further.
The heat required to change the phase of a substance is given by the equation:
Q= mL (Q= Heat required, m= mass, L= Latent Heat of Fusion/Evaporation/Anything else).
So, to convert ice at 0°C to water at 0°C
Q= 3.0 kg x 333 kJ/Kg
So, Q= 999 kJ
Total energy=(3423420+999)J
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