Question

What is the heat energy required to raise 20 kg of water from 25 degree celsius to 75 degree celsius?

Answer 1

Dear Student,

◆ Answer -

H = 4200 kJ

● Explanation -

# Given -

m = 20 kg = 20000 g

T1 = 25 ℃

T2 = 75 ℃

# Solution -

Heat energy required is calculated by -

H = m.c.∆T

H = 20000 × 4.2 × (75-25)

H = 4200000 J

H = 4200 kJ

Hence, the heat energy required to rise the temperature of the water is 4200 kJ.

Thanks dear. Hope this helps you..

Answer 2

Answer:

◆ Answer -

H = 4200 kJ

● Explanation -

# Given -

m = 20 kg = 20000 g

T1 = 25 ℃

T2 = 75 ℃

# Solution -

Heat energy required is calculated by -

H = m.c.∆T

H = 20000 × 4.2 × (75-25)

H = 4200000 J

H = 4200 kJ

Hence, the heat energy required to rise the temperature of the water is 4200 kJ.