What is the heat in joules required to raise the temperature of 25 grams of water from 0┬░ to 100┬░ Celsius?what is the heat in calories? specific heat of water = 4.18J/g┬░Celsius
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Answer:
10450 J
Explanation:
Q=m*c*t
Q=25*4.18*100
Q=10450 J
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