what is the heat in joules required to raise the temperature of 25g of water from 0"C to 100"C ? what is the heat in calories?
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we know, Q = ms del(theta).... so Q= (0.025*4200*100) = 10500J
S(water)= 4200 JKg^(-1)k^(-1)
mdmir1998:
2509.56 calorie as 4.2 J = 1 cal
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