Question

What is the heat needed to raise the temperature of 24.7 kg silver from 14.0 degrees celsius to 30.0 degrees celsius? specific heat capacity of silver is 236 j/(kg * c°)?

Answer 1

Q = mC∆T
Here Q is the heat needed
C is the specific heat capacity ,
∆T is the temperature ,

Here , m = 24.7 Kg , C = 236 J/kg.°C and ∆T = 30°C - 14°C = 16°C
Q = 24.7 × 236 × 16 J
Q = 93267.2 J = 93.2672 KJ

Answer 2

Let the heat energy required be Q and ¢ be the change in temperature of the silver and m the mass of the silver. C representing the heat capacity.

The formulae for getting the heat energy required is thus :

Q=mC¢

C=236J/Kg

M=24.7Kg

¢=30° - 14°=16°

Substituting this information in the formula we get :

236 × 16 × 24.7 = 93267.2Joules

Converting to kilo joules we get :

93267.2/1000=93.2672KJoules