what is the height of ac if AB is 100 cm and Angle A B C is 60°
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Answer:
As perimeter of ΔADC= perimeter of ΔADB
Let length of AD be ′l′ then,
l+x+80=60+l+(100−x)
⇒20=100−2x⇒x=40cm
∴ length of BD=(100−x)=60cm
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Answer:
length of bd is 60 cm
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