Question

What is the height of the cone if the volume of a right circular cone is 9856 cm³. If the diameter of the base is 28 cm? ​

Answer 1

$\huge \mathbb{ \purple{SOLUTION : }}$

Radius of cone = (28/2) cm = 14cm.

Let the height of the cone be h.

$\sf \: Volume \: of \: cone = 9856 \: cm {}^{3}$

$\sf \implies \frac{1}{3} \pi \: r {}^{2} h = 9856 \: cm {}^{3}$

$\sf \implies[ \frac{1}{3} \times \frac{22}{7} \times (14) ^{2} \times h] \: cm {}^{2} = 9856 \: cm {}^{3}$

$\sf \implies{ \color{red}{h = 48}}$

Therefore, the height of the cone is 48 cm.