Math, asked by ishanlinu007, 10 months ago

What is the height of the cylinder whose volume is 1.54 m^3 and diameter of base is 140 cm

Answers

Answered by kumbhareswarnim11
1

Answer:

140cm = 1.4m \\ volume = \pi {r}^{2} h \\  1.54 = 3.14 \times  ( \frac{1.4}{2} )^{2}  \times h \\ 1.54 = 3.14 \times 0.49\times h \\ h = 1.0009099181

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Answered by BlessedMess
21

Volume of cylinder = 1.54 m ³

and diameter of cylinder = 140 cm

Radius (r) = \frac{d}{2}=\frac{140}{2}=70 cm

Volume of cylinder = πr²h

⇒ 1.54 =  \frac{22}{7}  \times 0.7 \times 0.7 \times h

After simplifying, we get the value of h that is

h =  \frac{1.54 \times 7}{22 \times 0.7 \times 0.7}

⇒ h = 1

Hence, height of the cylinder is 1 m.

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