Question

what is the height of the trapezium if sum of it's parallel sides is 50cm and area as 75 sq cm. please answer fast​

Answer 1

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$\sf \: Area \: of \: trapezium = \frac{1}{2} \times \\ \sf (sum \: of \: parallel \: sides) \times (distance \: between \: them)$

$\sf \frac{1}{ \cancel2} \times \cancel{50} \: {}^{25} cm \times h = 75$

$\sf \: h = \frac{75}{25} = 3m$