What is the highest and lowest resistance that can be secured by the
combination of four resistors of 4 Ω, 6 Ω,8 Ω,24 Ω
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Answer:
R = 4 + 8 + 12 + 24 = 48 Ω. (b) Lowest resistance can be obtained by connecting the four coils in parallel and we obtain highest resistance in series and lowest in parallel
Explanation:
thank you i hope it's help you 1/4 +1/8+1/12+1/24=lowest resistance
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