Question

What is the highest and lowest total resistance that can be secured by
combinations of four coils of resistance 4 ohm,8 ohm,12 ohm and 24 ohm?​

Answer 1

Answer:

Hey mate the answer is :-

Explanation:

4 Ω, 8 Ω, 12 Ω, 24 Ω? R = 4 + 8 + 12 + 24 = 48 Ω.

Answer 2

Answer:

highest resistance can be obtained by connecting the four coils in series . then R=R1+R2+R3+R4

R=4+8+12+24=48 ohm

lowest resistance can be obtained by connecting the four coils in parallel.

then

$\frac{1}{r } = \frac{1}{4} + \frac{1}{8} + \frac{1}{12} + \frac{1}{24} = \frac{12}{24} \\ 2ohm$

R=2ohm Mark me BRAINLIST plz ❤❤