Question

what is the highest common factor of 35 n²m, 21 m² n

Answer 1

Step-by-step explanation:

35n²m = 5×7×mn×n

21m²n = 3×7×mn×m

hcf = 7mn

Answer 2

Answer:

7mn

Step-by-step explanation:

You just need to select which is common.

In 21 and 35, 7 is common.

In n²m and m²n, mn is common.

So at last, 7mn is common which is hcf.

hope it helps.

Thank You

please mark brainliest