What is the highest lowest total resistance that can be obtained by combination of four coils of resistance 4 ohm 8 ohm 10 ohm and 20 Ohm
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The highest resistance is secured when all the four coils connected in the series .
in that case
R=4+8+12+24
= 48 ohms
The lowest resistance is secured win all the four coils are connected in parallel
In that case,
1/R= 1/4 + 1/8 + 1/12 + 1/48
=12/24
R = 24/12
R = 2 ohms
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