Question

what is the highest total resistance that can be secured by a combination of 4 coils of resistance 4ohm ,6ohm, 8ohm, 100ohm​

Answer 1

Explanation:

(a)Highest will be by series =4+12+8+24=48ohms

(b)Lowest will be by parallel =1/R=1/4+1/8+1/24+1/12=12/24=1/2

so R=2

Answer 2

Answer:

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Explanation:

Ans: Given resistances R1 =4 Ω, R2=8 Ω, R3=12Ω, and R4=24Ω.

(a) If these coils are connected in series, then the equivalent resistance will

be the highest, as R=R1+R2+R3+R4

∴ R=4+8+12+24 = 24Ω

(b) If these coils are connected in parallel, then the equivalent resistance will be the lowest, given by

⇒R=2 Ω

∴ 2 Ω is the lowest total resistance.